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The nth term of a progression is `3^(n + 1)`. Show that it is a G.P. Also, find its 5th term.
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nth term = `3^(n + 1)`
1st term = `3^(1 + 1)`
= 32
= 9
2nd term = `3^(2 + 1)`
= 33
= 27
`(a_2)/(a_1) = 27/9`
= 3
If we are getting a constant common ratio, then this series is a GP.
5th term = `3^(5 + 1)`
= 36
= 729
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