Question

The normal boiling point of water is 100°C or 212°F and the freezing point of water is 0°C or 32°F. Find the value of F for 38°C

Answer 1

For 38°C To find F

(1) ⇒ C = `5/9("F" - 32^circ)`

`9/5"C"` = F – 32°

F = `9/5"C" + 32^circ`

= `9/5 xx 38^circ + 32`

= `342/5 + 32`

= `(342 + 160)/5`

= `502/5`

F = 100.4°