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प्रश्न
The motion of a simple pendulum executing S.H.M. is represented by the following equation.
y = Asin(πt + Φ), where time is measured in seconds. The length of the pendulum is ______.
पर्याय
97.23 cm
25.3 cm
99.4 cm
406.1 cm
MCQ
रिकाम्या जागा भरा
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उत्तर
The motion of a simple pendulum executing S.H.M. is represented by the following equation.
y = Asin(πt + Φ), where time is measured in seconds. The length of the pendulum is 99.4 cm.
Explanation:
During the time period of SHM,
`T = 2pisqrt(l/g)` and, `omega = (2pi)/T`
Hence, `omega = (2pi)/(2pi)sqrt(g/l)`
`omega = sqrt(g/l)`
`l = g/omega^2`
By comparing with the above equation, we get;
ω = π
Hence, `l = g/(pi^2) ≈ 99.4` cm
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