Question

The molar conductivity of a 0.02 mol dm⁻³ solution of sodium hydroxide is 230.5 Ω⁻¹ cm² mol⁻¹. What is its conductivity?

पर्याय

• 0.01155 Ω⁻¹ cm⁻¹

• 0.02308 Ω⁻¹ cm⁻¹

• 0.00461 Ω⁻¹ cm⁻¹

• 0.05613 Ω⁻¹ cm⁻¹

Answer 1

0.02308 Ω⁻¹ cm⁻¹

Explanation:

`∧_m = (k xx 1000)/C`

k = `(∧_m C)/1000`

= `(0.02  mol  dm^-3 xx 230.5  Ω^-1  cm^2  mol^-1)/(1000  cm^3  dm^-3)`

= 0.00461 Ω⁻¹ cm⁻¹