Question

The minute hand of clock is10cm long. Find the area of the face of the clock described by the minute hand between 8am and 8:25 am

Answer 1

Radius of minute hand (r) = 10 cm

For 1 hr = 60 min, minute hand completes one revolution = 360°

60 min = 360°

1 min = 6°

From 8 am to 8:25 am it is 25 min angle subtended = 6° × 25 = 150° = 𝜃

Area described =`theta/360^@× pir^2`

=`150/360×22/7`× 10 × 10

=`(250×11)/3`

=`2750/3 cm^2`