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प्रश्न
The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.
| Marks: | 20 -30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
| Frequency: | P | 15 | 25 | 20 | q | 8 | 10 |
The median of the following data is 50. Find the values of ‘p’ and ‘q’, if the sum of all frequencies is 90. Also find the mode of the data.
| Marks obtained | Number of students |
| 20 – 30 | p |
| 30 – 40 | 15 |
| 40 – 50 | 25 |
| 50 – 60 | 20 |
| 60 – 70 | q |
| 70 – 80 | 8 |
| 80 – 90 | 10 |
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उत्तर
The given series is in inclusive form. Converting it to exclusive form and preparing the cumulative frequency table, we have
| Class interval | Frequency (fi ) | Cumulative Frequency (c.f.) |
| 20 – 30 | p | p |
| 30 – 40 | 15 | p + 15 |
| 40 – 50 | 25 | p + 40 |
| 50 – 60 | 20 | p + 60 |
| 60 – 70 | q | p + q + 60 |
| 70 – 80 | 8 | p + q + 68 |
| 80 – 90 | 10 | p + q + 78 |
| 78 + p + q = 90 |
Median = 50 It lies in the interval 50 – 60, so the median class is 50 – 60.
Now, we have
l = 50, h = 10, f = 20, F = p + 40, N = 90
We know that
Median = `"l" + {("N"/2 - "f")/"f"} xx "h"`
`50 = 50 + (45 - ("p" + 40))/20xx10`
⇒ 0 = `(5 - "p")/2`
⇒ p = 5
And,
p + q + 78 = 90
⇒ p + q = 12
⇒ q = 12 − 5 = 7
Mode = `"l" + ("f"_1 - "f"_0)/(2"f"_1 - "f"_0 - "f"_2)."h"`
= `40 + (25 - 15)/(2(25) - 15 - 20)xx10`
= `40 + 100/15`
= 40 + 6.67
= 46.67
