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प्रश्न
The median of the following data is 137. Find the values of x and y, given that total of frequencies is 68.
| Class | Frequency |
| 65-85 | 4 |
| 85-105 | 5 |
| 105-125 | x |
| 125-145 | 20 |
| 145-165 | 14 |
| 165-185 | y |
| 185-205 | 4 |
बेरीज
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उत्तर
Given: Median = 137
Total frequency N = 68
4 + 5 + x + 20 + 14 + y + 4 = 68
47 + x + y = 68
x + y = 68 − 47
x + y = 21 ...(i)
`N/2 = 68/2`
= 34
| Class | Frequency | C.F. |
| 65-85 | 4 | 4 |
| 85-105 | 5 | 9 |
| 105-125 | x | 9 + x |
| 125-145 | 20 | 29 + x |
| 145-165 | 14 | 43 + x |
| 165-185 | y | 43 + x + y |
| 185-205 | 4 | 47 + x + y |
| Total | `sumf = 68` |
Here, the maximum frequency is 20, so the modal class is 125-145.
Therefore,
l = 125, h = 20, f = 20, c.f. = (9 + x)
Median = `l + ((n/2 - c.f.)/f) xx h`
`137 = 125 + ((34 - (9 + x))/20) xx 20`
137 − 125 = 34 − 9 − x
12 = 25 − x
x = 25 − 12
∴ x = 13
Put x = 13 in quation no. (i)
13 + y = 21
y = 21 − 13
∴ y = 8
Hence, the values of x and y are 13 and 8.
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