Question

The mass number of He is 4 and that for sulphur is 32. The radius of sulphur nuclei is larger than that of helium by:

पर्याय

• \[\sqrt{8}\]

• 4

• 2

• 8

Answer 1

2

Explanation:

R_s/R_He = (A_s/A_He)^1/3 = (32/4)^1/3 = 2 Hence, radius of sulphur nuclei is larger than helium by 2.