Advertisements
Advertisements
प्रश्न
The magnetic field at the centre of a current carrying circular coil of area ‘A’ is ‘B’. The magnetic moment of the coil is ______.
(μ0 = permeability of free space)
पर्याय
`(2B)/mu_0 sqrt (A^3/pi)`
`(BA^2)/(4 mu_0 pi)`
`(2 pi)/mu_0 sqrt (A^3)`
`mu_0/(2B) sqrt (A^3/pi)`
MCQ
रिकाम्या जागा भरा
Advertisements
उत्तर
The magnetic field at the centre of a current carrying circular coil of area ‘A’ is ‘B’. The magnetic moment of the coil is `bbunderline((2B)/mu_0 sqrt (A^3/pi))`.
Explanation:
We know,
M = iA and
A = πR2
Also,
B = `(mu_0 i)/(2R)`
∴ i = `(2BR)/(mu_0)`
∴ i = `(2B)/mu_0 xx sqrt(A/pi)`
∴ m = `(2B)/mu_0 sqrt(A/pi) xx A`
= `(2B sqrt(A^3))/(mu_0 sqrt pi)`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
