Advertisements
Advertisements
प्रश्न
The magnetic field at the centre of a circular current carrying loop of radius 12 cm is 6 × 10−6 T. What will be the magnetic moment of the loop?
संख्यात्मक
Advertisements
उत्तर
Data: R = 12 cm = 12 × 10−2 m, B = 6 × 10−6 T, `µ_0/(4π)` = 10−7 T·m/A
B = `(µ_0NI)/(2R)`
The magnetic moment of the coil,
M = NIA = NI (πR2)
= `(2BR)/µ_0(πR^2)`
= `(2BR^3)/((µ_0/(4π)) xx 4)`
= `(BR^3)/(2((µ_0)/(4π)))`
= `((6 xx 10^-6)(12 xx 10^-2)^3)/(2 xx 10^-7)`
= 30 × 1728 × 10−6
= 5.184 × 10−2 A.m2
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
