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प्रश्न
The magnetic field at point P on the axis of a circular loop of radius R, carrying current I, at a distance x from the centre is:
पर्याय
\[B = \frac{\mu_0 I R^2}{2(x^2+R^2)^{3/2}}\]
\[B = \frac{\mu_0 I R^2}{(x^2+R^2)^{3/2}}\]
\[B = \frac{\mu_0 I R}{2(x^2+R^2)^{3/2}}\]
\[B = \frac{\mu_0 I R^2}{2(x^2+R^2)}\]
MCQ
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उत्तर
The exact axial field of a circular loop of radius R carrying current I at an axial distance x is \(B = \frac{\mu_0 I R^2}{2(x^2+R^2)^{3/2}}\). This is the starting point of the magnetic dipole derivation.
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