मराठी

The Locus of the Points of Trisection of the Double Ordinates of a Parabola is a - Mathematics

Advertisements
Advertisements

प्रश्न

The locus of the points of trisection of the double ordinates of a parabola is a 

पर्याय

  • pair of lines 

  •  circle

  • parabola 

  • straight line 

MCQ
Advertisements

उत्तर

 parabola 

Suppose PQ is a double ordinate of the parabola \[y^2 = 4ax\] 

Let R and be the points of trisection of the double ordinates.
Let \[\left( h, k \right)\] be the coordinates of R. 

Then, we have:
OL = h  and RL = k  

\[\therefore RS = RL + LS = k + k = 2k\]
\[ \Rightarrow PR = RS = SQ = 2k\]
\[ \Rightarrow LP = LR + RP = k + 2k = 3k\]

Thus, the coordinates of P are \[\left( h, 3k \right)\] which lie on \[y^2 = 4ax\] 

∴ \[9 k^2 = 4ah\] 

Hence, the locus of the point (hk) is \[9 y^2 = 4ax\]  i.e.  \[y^2 = \left( \frac{4a}{9} \right)x\] which represents a parabola.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 25: Parabola - Exercise 25.3 [पृष्ठ २९]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
पाठ 25 Parabola
Exercise 25.3 | Q 7 | पृष्ठ २९

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the equation of the parabola that satisfies the following condition:

Focus (6, 0); directrix x = –6


Find the equation of the parabola that satisfies the following condition:

Vertex (0, 0) focus (–2, 0)


Find the equation of the parabola that satisfies the following condition:

Vertex (0, 0) passing through (2, 3) and axis is along x-axis


Find the equation of the parabola that satisfies the following condition:

Vertex (0, 0), passing through (5, 2) and symmetric with respect to y-axis.


If a parabolic reflector is 20 cm in diameter and 5 cm deep, find the focus.


An arch is in the form of a parabola with its axis vertical. The arch is 10 m high and 5 m wide at the base. How wide is it 2 m from the vertex of the parabola?


The cable of a uniformly loaded suspension bridge hangs in the form of a parabola. The roadway which is horizontal and 100 m long is supported by vertical wires attached to the cable, the longest wire being 30 m and the shortest being 6 m. Find the length of a supporting wire attached to the roadway 18 m from the middle.


An equilateral triangle is inscribed in the parabola y2 = 4 ax, where one vertex is at the vertex of the parabola. Find the length of the side of the triangle.


Find the equation of the parabola whose: 

 focus is (1, 1) and the directrix is x + y + 1 = 0


Find the equation of the parabola whose: 

 focus is (0, 0) and the directrix 2x − y − 1 = 0

 


Find the equation of the parabola whose: 

 focus is (2, 3) and the directrix x − 4y + 3 = 0.


Find the equation of the parabola whose focus is the point (2, 3) and directrix is the line x − 4y + 3 = 0. Also, find the length of its latus-rectum.

 


Find the equation of the parabola if the focus is at (0, −3) and the vertex is at (−1, −3)


Find the equation of the parabola if the focus is at (a, 0) and the vertex is at (a', 0) 


At what point of the parabola x2 = 9y is the abscissa three times that of ordinate? 


Find the equation of a parabola with vertex at the origin, the axis along x-axis and passing through (2, 3).


Find the equation of the parabola whose focus is (5, 2) and having vertex at (3, 2). 


Find the coordinates of points on the parabola y2 = 8x whose focal distance is 4.   


If the line y = mx + 1 is tangent to the parabola y2 = 4x, then find the value of m


Write the equation of the parabola with focus (0, 0) and directrix x + y − 4 = 0.


PSQ is a focal chord of the parabola y2 = 8x. If SP = 6, then write SQ


The equation of the parabola whose vertex is (a, 0) and the directrix has the equation y = 3a, is 


The parametric equations of a parabola are x = t2 + 1, y = 2t + 1. The cartesian equation of its directrix is 


If the coordinates of the vertex and the focus of a parabola are (−1, 1) and (2, 3) respectively, then the equation of its directrix is 


The equation of the directrix of the parabola whose vertex and focus are (1, 4) and (2, 6) respectively is 


The equations of the lines joining the vertex of the parabola y2 = 6x to the points on it which have abscissa 24 are ______.


The equation of the parabola whose focus is the point (2, 3) and directrix is the line x – 4y + 3 = 0 is ______.


If the line y = mx + 1 is tangent to the parabola y2 = 4x then find the value of m.


Find the equation of the following parabolas:

Vertex at (0, 4), focus at (0, 2)


The equation of the parabola having focus at (–1, –2) and the directrix x – 2y + 3 = 0 is ______.


If the vertex of the parabola is the point (–3, 0) and the directrix is the line x + 5 = 0, then its equation is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×