मराठी

The line y = 4 divides the join of points (6, 7) and (4, −1) in the ratio ______.

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प्रश्न

The line y = 4 divides the join of points (6, 7) and (4, −1) in the ratio ______.

पर्याय

  • 3 : 5

  • 5 : 3

  • 1 : 5

  • 5 : 1

MCQ
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उत्तर

The line y = 4 divides the join of points (6, 7) and (4, −1) in the ratio 3 : 5.

Explanation:

Any point on the line \[y = 4\], can be defined as \[(x, 4).\]

Let point \[(x, 4)\] divide line joining \[(6, 7)\] and \[(4, -1)\] in ratio \[k : 1.\]

By section-formula,

\[(x, y) = \left(\frac{m_1x_2 + m_2x_1}{m_1 + m_2}, \frac{m_1y_2 + m_2y_1}{m_1 + m_2}\right)\]

Substituting values we get:

⇒ \[(x, 4) = \left(\frac{k \times 4 + 1 \times 6}{k + 1}, \frac{k \times -1 + 1 \times 7}{k + 1}\right)\]

⇒ \[(x, 4) = \left(\frac{4k + 6}{k + 1}, \frac{-k + 7}{k + 1}\right)\]

⇒ \[4 = \frac{-k + 7}{k + 1}\]

⇒ \[4(k + 1) = -k + 7\]

⇒ \[4k + 4 = -k + 7\]

⇒ \[4k + k = 7 - 4\]

⇒ \[5k = 3\]

⇒ \[k = \frac{3}{5}\]

Substituting value of \[k\] in \[k : 1\], we get:

⇒ \[\frac{3}{5} : 1\]

⇒ 3 : 5

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पाठ 13: Section Formula and Mid-Point Formula - EXERCISE 13(A) [पृष्ठ १७४]

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सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 13 Section Formula and Mid-Point Formula
EXERCISE 13(A) | Q 1. (d) | पृष्ठ १७४
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