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प्रश्न
The line 2x − 3y = 12, meets x-axis at point A and y-axis at point B, then ______.
पर्याय
A = (6, 0) and В = (0, –4)
A = (0, 4) and B = (6, 0)
A = (0, –4) and B (–6, 0)
A = (–6, 0) and B = (4, 0)
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उत्तर
The line 2x − 3y = 12, meets x-axis at point A and y-axis at point B, then A = (6, 0) and В = (0, –4).
Explanation:
We know that,
y-coordinate at x-axis = 0.
Let point A be (a, 0).
Since,
Line 2x − 3y = 12 meets x-axis at point A.
∴ Point A(a, 0) satisfies the equation 2x − 3y = 12.
⇒ 2a − 3(0) = 12
⇒ 2a − 0 = 12
⇒ 2a = 12
⇒ `12/2 = 6`
∴ A = (a, 0) = (6, 0).
We know that,
x-coordinate at y-axis = 0.
Let point B be (0, b).
Since,
Line 2x − 3y = 12 meets y-axis at point B.
∴ Point B(0, b) satisfies the equation 2x − 3y = 12.
⇒ 2(0) − 3b = 12
⇒ 0 − 3b = 12
⇒ −3b = 12
⇒ b = `12/(−3)` = −4
∴ B = (0, b) = (0, −4)
