Question

The inversion of cane sugar is represented as \[\ce{C12H22O11 + H2O -> C6H12O6 + C6H12O6}\].

It is a ______.

पर्याय

• second order reaction

• unimolecular reaction

• pseudo-unimolecular reaction

• zero order reaction

Answer 1

The inversion of cane sugar is represented as \[\ce{C12H22O11 + H2O -> C6H12O6 + C6H12O6}\].

It is a pseudo-unimolecular reaction.

Explanation:

The given reaction is \[\ce{C12H22O11 + H2O -> C6H12O6 + C6H12O6}\]

This reaction involves two reactants: cane sugar and water. But, since water is present in a very large excess, its concentration remains practically constant during the reaction. Therefore, the rate law depends only on the concentration of cane sugar. So, although it is actually a bimolecular reaction, it behaves like a unimolecular (first-order) reaction. This type of reaction is called a pseudo-unimolecular reaction.