Question

The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm³ of wood has a mass of 0.6 g.

`["Assume "pi=22/7]`

 

Answer 1

Inner radius (r₁) of cylindrical pipe = (24/2)cm = 12 cm

Outer radius (r₂) of cylindrical pipe = (28/2)cm = 14 cm

Height (h) of pipe = Length of pipe = 35 cm

`"Volume of pipe "= pi(r_2^2-r_1^2)h`

`=[22/7xx(14^2-12^2)xx35]cm^3`

= 110 x 52 cm³

= 5720 cm³

Mass of 1 cm³ wood = 0.6 g

Mass of 5720 cm³ wood = (5720 × 0.6) g

= 3432 g

= 3.432 kg