Advertisements
Advertisements
प्रश्न
The index number by the method of aggregates for the year 2010, taking 2000 as the base year, was found to be 116. If sum of the prices in the year 2000 is ₹ 300, find the values of x and y in the data given below
| Commodity | A | B | C | D | E | F |
| Price in the year 2000 (₹) | 50 | x | 30 | 70 | 116 | 20 |
| Price in the year 2010 (₹) | 60 | 24 | y | 80 | 120 | 28 |
बेरीज
Advertisements
उत्तर
| Base price (₹) in 2000 P0 |
Price(₹) in 2010 P1 |
|
| A | 50 | 60 |
| B | x | 24 |
| C | 30 | y |
| D | 70 | 80 |
| E | 116 | 120 |
| F | 20 | 28 |
| ∑P0 = 286 + x | ∑P1 = 312 + y |
Given ∑P0 = 300
⇒ x = 300 - 286 = 14
Index number P01 = 116
P01 = `( ∑P_1)/( ∑P_0) xx 100`
116 = `(312 + y)/(300) xx 100`
⇒ 116 x 3 = 312 + y
⇒ y = 36
∴ x = 14, y = 36
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
