Question

The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by:

पर्याय

• `(t_Q)/150 = (t_P - 180)/100`

• `(t_Q)/100 = (t_P - 30)/150`

• `(t_P)/180 = (t_Q - 40)/100`

• `(t_P)/100 = (t_Q - 180)/150`

Answer 1

`bb((t_Q)/100 = (t_P - 30)/150)`

Explanation:

The graph shows that the total change in temperature for Scale P(ΔT_P) is 150 units. The upper value on the graph for scale P is 180 P.

LFP_P = 180 − 150

= 30° P

The graph shows the line starting from the vertical axis where t_Q = 0. The total change for Scale Q(ΔT_Q) is 100 units.

LFP_Q = 0° Q

The general relationship for any temperature scale is:

`"Temperature - Lower Fixed Point (LFP)"/"Number of Divisions"` = Constant

The conversion formula for both scales:

`(t_p - LFP_P)/("Division"_P) = (t_Q - LFP_Q)/("Division"_Q)`

`(t_P - 30)/150 = (t_Q - 0)/100`

`(t_Q)/100 = (t_P - 30)/150`