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प्रश्न
The gradient of the curve passing through (4, 0) is given by `"dy"/("d"x) - "y"/x + (5x)/((x + 2)(x - 3))` = 0 if the point (5, a) lies on the curve, then the value of a is ______.
पर्याय
`67/12`
`5 sin 7/12`
`5 log 7/12`
None of these
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उत्तर
The gradient of the curve passing through (4, 0) is given by `"dy"/("d"x) - "y"/x + (5x)/((x + 2)(x - 3))` = 0 if the point (5, a) lies on the curve, then the value of a is `underlinebb(5 log 7/12)`.
Explanation:
The differential equation is
`"dy"/("d"x) - "y"/x = - (5x)/((x + 2)(x - 3))`
I.F = `"e"^(int(-1/x)"d"x) = "e"^(-"ln" x) = 1/x`
Solution is
`"y"(1/x) = int(1/x) xx (5x)/((x + 2)(x - 3))"d"x = "ln"((x + 2)/(x - 3)) + "C"`
It passes through (4, 0), so C = – ln 6
∴ y = `x "ln" {((x + 2))/(6(x - 3))}`
Putting (5, a),
we get a = `5 ln (7/12)`
