Question

The function `f(x) = (x^2 - 25)/(x + 5)` is continuous at x =

पर्याय

• – 5

• x ∈ R

• x ∈ R – |– 5|

• None of these

Answer 1

x ∈ R – |– 5|

Explanation:

At `x` = – 5, function f is not defined

∴ `f` is discontinuous at `x` = – 5

At `x = c ≠ - 5`

`lim_(x -> 0) f(x) = lim_(x -> 0) (x^2 - 25)/(x + 5)` = – 5

And `f(0)` = 0 – 5

 ∴ `f` is continous for all x ∈ R – |– 5|