Question

The frequency of revolution of a charged particle moving in a circular path in a magnetic field is:

पर्याय

• \[\nu = \frac{2\pi qB}{m}\]

• \[\nu = \frac{qB}{2\pi m}\]

• \[\nu = \frac{qBm}{2\pi}\]

• \[\nu = \frac{2\pi m}{qB}\]

Answer 1

The frequency of revolution is \[\nu = \frac{qB}{2\pi m}\]. Since \[\omega = \frac{qB}{m}\] and \[\nu = \frac{\omega}{2\pi}\], the frequency depends only on charge q, magnetic field B, and mass m — it is independent of speed and radius.