Question

The force between two charges 0.06 m apart is 5 N. If each charge is moved towards the other by 0.01 m, then the force between them will become ______.

पर्याय

• 7.20 N

• 11.25 N

• 22.50 N

• 45.00 N

Answer 1

The force between two charges 0.06 m apart is 5 N. If each charge is moved towards the other by 0.01 m, then the force between them will become 11.25 N.

Explanation:

The force between two charges is given by

`F = (Kq_1q_2)/(r^2)`

`F prop 1/(r^2)`

= `(F_1)/(F_2) = ((r_2)/(r_1))^2`

= `5/(F^2) = ((0.04)/(0.06))^2`

= F₂ ​= 11.25 N