Question

The following is the p.d.f. of r.v. X :

f(x) = `x/8`, for 0 < x < 4 and = 0 otherwise

P ( 1 < x < 2 )

Answer 1

 P (1 < x < 2)

= ` int_(1)^2 f (x) dx`

= ` int_(1)^2 x/8 dx`

`1/8[x^2/2]_1^2`

=`1/8[4/2-1/2]`

=`3/16`