Question

The first term of an A.P. is 5, the common difference is 3 and the last term is 80;

Answer 1

In the given problem, we are given an A.P whose,

First term (a) = 5

Last term (`a_n`) = 80

Common difference (d)  = 3

We need to find the number of terms present in it (n)

So here we will find the value of n using the formula, `a_n = a + (n - 1)d`

So, substituting the values in the above-mentioned formula

80 = 5 + (n - 1)3

80 - 5 = 3n - 3

75 + 3 = 3n

`n = 78/3`

n = 26

Thus n = 26

Therefore, the number of terms present in the given A.P is 26