Question

The equivalent conductances of two strong electrolytes at infinite dilution in H₂O (where ions move freely through a solution) at 25°C are given below:

\[\ce{\Lambda^{\circ}_{CH_3COONa}}\] = 91.0 S cm²/equiv.

\[\ce{\Lambda^{\circ}_{HCl}}\] = 426.2 S cm²/equiv.

What additional information/quantity does one need to calculate Λ° of an aqueous solution of acetic acid?

पर्याय

• Λ° of NaCl

• Λ° of CH₃COOK

• The limiting equivalent conductance of H⁺.

• Λ° of chloroacetic acid (ClCH₂COOH)

Answer 1

Λ° of NaCl

Explanation:

According to Kohlrausch law,

\[\ce{\Lambda^{\circ}_{CH_3COOH} = \Lambda^{\circ}_{HCl} + \Lambda^{\circ}_{CH_3COONa} - \Lambda^{\circ}_{NaCl}}\]

∴ \[\ce{\Lambda^{\circ}_{NaCl}}\] is required to calculate \[\ce{\Lambda^{\circ}_{CH_3COOH}}\].