Question

The equation of tangent to the curve y = 3x² - x + 1 at the point (1, 3) is 

(a) y=5x+2

(b)y=5x-2

(c)y=1/5x+2

(d)y=1/5x-2

 

Answer 1

y = 5x - 2

`dy/dx=6x-1" at "(1,3)`

Slope of the tangent at (1, 3) = (6 - 1) = 5

Equation of tangent is y - y₁ = m(x - x₁)

y - 3 = 5(x - 1)

5x - y - 2 = 0
y = 5x - 2