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The equation of the tangent to the parabola, \[y^{2}=16x\text{ at}(1,4)\] is______.
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\[x=4y\]
\[2x+y+2=0\]
\[y=4x\]
\[2x-y+2=0\]
MCQ
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The equation of the tangent to the parabola, \[y^{2}=16x\text{ at}(1,4)\] is \[2x-y+2=0\].
Explanation:
The parabola is \[y^2=16x,\mathrm{so~}4a=16\Rightarrow a=4.\]
The standard equation of the tangent to \[y^2=4ax\] at a points \[(x_1,y_1)\] is:
\[y\cdot y_1=2a(x+x_1)\]
At the point (1,4) :
\[y\cdot4=2(4)(x+1)\]
\[4y=8x+8\]
\[8x-4y+8=0\]
\[2x-y+2=0\]
shaalaa.com
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