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प्रश्न
The equation of normal to the curve y = loge x at the point P(1, 0) is ______.
पर्याय
2x + y = 2
x - 2y = 1
x - y = 1
x + y = 1
MCQ
रिकाम्या जागा भरा
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उत्तर
The equation of normal to the curve y = loge x at the point P(1, 0) is x + y = 1.
Explanation:
We have, y = loge x `=> "dy"/"dx" = 1/x`
∴ Slope of normal at P(1, 0)
`= - 1/("dy"/"dx")_((1, 0)`
`= (- 1)/1` = - 1
∴ Equation of normal at P(1, 0)
⇒ y - 0 = (- 1)(x - 1)
⇒ y = - x + 1
⇒ x + y = 1
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Application of Derivative in Geometry
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