Question

The equation of normal to the curve y = 3x² − x + 1 at (1, 3) is ______.

पर्याय

• x − 5y − 16 = 0

• x + 5y − 16 = 0

• x − 5y + 16 = 0

• −5y − x − 16 = 0

Answer 1

The equation of normal to the curve y = 3x² − x + 1 at (1, 3) is x + 5y − 16 = 0.

Explanation:

Differentiate to find the slope of the tangent at x = 1. Normal slope is the negative reciprocal of the tangent slope. Substitute the point (1, 3) into point-slope form to get the equation.