मराठी

The equation for the burning of octane is: 2CA8HA18+25OA2⟶16COA2+18HA2O What volume, at STP, is occupied by 8 moles? - Chemistry

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प्रश्न

The equation for the burning of octane is:

\[\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}\]

What volume, at STP, is occupied by 8 moles?

संख्यात्मक
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उत्तर

1 mole of CO2 occupies = 22.4 L at STP.

∴ 8 moles of CO2 will occupy = 22.4 × 8

= 179.2 L at STP

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पाठ 5: Mole Concept And Stoichiometry - Exercise 8 [पृष्ठ १२२]

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फ्रँक Chemistry Part 2 [English] Class 10 ICSE
पाठ 5 Mole Concept And Stoichiometry
Exercise 8 | Q 3.2 | पृष्ठ १२२
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