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The enthalpy of atomisation for the reaction CHX4(g)⟶C(g)+4H(g) is 1665 kJ mol–1. What is the bond energy of C−H bond? - Chemistry

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प्रश्न

The enthalpy of atomisation for the reaction \[\ce{CH4(g) -> C(g) + 4H(g)}\] is 1665 kJ mol–1. What is the bond energy of \[\ce{C – H}\] bond?

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उत्तर

The reaction presented in the question is \[\ce{CH4(g) -> C(g) + 4H(g)}\]

Now, ΔaH = 1665 kJ mol–1

The mean bond enthalpy of the \[\ce{C – H}\] bond should be used here. For the atomisation of 4 moles of \[\ce{C – H}\] bonds, the value is 1665 mol–1. So, per mole energy = 1665/4 = 416.2 kJ / mol–1.

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पाठ 6: Thermodynamics - Multiple Choice Questions (Type - I) [पृष्ठ ७२]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 6 Thermodynamics
Multiple Choice Questions (Type - I) | Q 25 | पृष्ठ ७२
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