Question

The energy levels of an atom of a certain element are shown in the given figure. Which one of the transitions A, B, C, D or E will result in the emission of photons of electromagnetic radiation of wavelength 618.75 nm? Support your answer with mathematical calculations.

Answer 1

The wavelength emitted λ = 618.75 nm

∴ Corresponding energy E = h `c/λ`

= `( 6.6 xx 10^-34 xx 3 xx 10^8 )/( 618.75 xx 10^-9 xx 1.6 xx 10^-19) e^V`

= `( 6.6 xx 3 )/( 618.75 xx 1.6 ) xx 100`

= 2eV

This corresponds to the transition D.
In which energy emitted is ΔE = - 1 - ( - 3 ) = 2eV