Question

The electric potential on the surface of a uniformly charged spherical shell of radius \[R\] carrying charge \[q\] is:

पर्याय

• \[V = \frac{1}{4\pi\varepsilon_0}\frac{q}{R^2}\]

• \[V = \frac{1}{4\pi\varepsilon_0}\frac{q}{2R}\]

• \[V = \frac{1}{4\pi\varepsilon_0}\frac{q}{R}\]

• \[V = 0\]

Answer 1

On the surface \[(r = R)\], the potential is \[V = \frac{1}{4\pi\varepsilon_0}\frac{q}{R}\]. This value is continuous with both the outside expression (setting \[r = R\]) and the constant interior value, ensuring potential is continuous everywhere.