Question

The eccentricity of the ellipse 4x² + 9y² = 36 is

पर्याय

• \[\frac{1}{2\sqrt{3}}\]

   

• \[\frac{1}{\sqrt{3}}\]

   

• \[\frac{\sqrt{5}}{3}\]

   

• \[\frac{\sqrt{5}}{6}\]

   

Answer 1

\[4 x^2 + 9 y^2 = 36\]
\[ \Rightarrow \frac{x^2}{9} + \frac{y^2}{4} = 1 . . (1)\]
\[\text{ Compairing equation (1 ) with }\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1,\text{ we get }\]
\[ a^2 = 9\text{ and }b^2 = 4\]
Here, a > b, so the major and the minor axes of the given ellipse are along the x - axis and the y - axis, respectively.
\[\text{ Now, }e = \sqrt{1 - \frac{b^2}{a^2}}\]
\[ \Rightarrow e = \sqrt{1 - \frac{4}{9}}\]
\[ \Rightarrow e = \sqrt{\frac{5}{9}}\]
\[ \Rightarrow e = \frac{\sqrt{5}}{3}\]