Advertisements
Advertisements
प्रश्न
The domain of the function f defined by f(x) = `sqrt(4 - x) + 1/sqrt(x^2 - 1)` is equal to ______.
पर्याय
`(– oo, – 1) ∪ (1, 4]`
`(– oo, – 1] ∪ (1, 4]`
`(– oo, – 1) ∪ [1, 4]`
`(– oo, – 1) ∪ [1, 4)`
MCQ
रिकाम्या जागा भरा
Advertisements
उत्तर
The domain of the function f defined by f(x) = `sqrt(4 - x) + 1/sqrt(x^2 - 1)` is equal to `(– oo, – 1) ∪ (1, 4]`.
Explanation:
Given that: f(x) = `sqrt(4 - x) + 1/sqrt(x^2 - 1)`
f(x) is defined if
4 – x ≥ 0 or x2 – 1 > 0
⇒ – x ≥ – 4 or (x – 1)(x + 1) > 0
⇒ x ≤ 4 or x < – 1 and x > 1
∴ Domain of f(x) is `(– oo, – 1) ∪ [1, 4]`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
