Question

The distance of the gate of a temple from its base is `sqrt(3)` times it height. Find the angle of elevation of the top of the temple.

Answer 1

Let AB be the temple and C be the position of its gate. 
Let h be the height of the temple. Then, 
AB= h 
BC = Distance of the gate of temple from its base = `sqrt(3)`h 
In ΔABC, 

tanθ = `"AB"/"BC"`

⇒ `tanθ = h/(sqrt(3)h) = 1/sqrt(3)`

But , `tan30^circ = 1/sqrt(3)`

∴ θ = `30^circ`

Thus , the angle of elevation of the top of the temple is `30^circ`.