Advertisements
Advertisements
प्रश्न
The distance between the lines represented by the equation 4x² + 4xy + y² − 6x − 3y − 4 = 0 is
पर्याय
\[\frac{1}{\sqrt{5}}\] units
\[\frac{1}{5}\] units
√5 units
5 units
MCQ
Advertisements
उत्तर
√5 units
Explanation:
4x² + 4xy + y² − 6x − 3y − 4 = 0
∴ (2x + y)² − 3(2x + y) − 4 = 0
∴ (2x + y − 4)(2x + y + 1) = 0
∴ The separate equations of lines are
2x + y − 4 = 0
and 2x + y + 1 = 0
∴ Distance between the lines = \[\frac{1+4}{\sqrt{4+1}}\]
\[=\frac{5}{\sqrt{5}}=\sqrt{5}\mathrm{units}\]
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
