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The displacement of a particle is given by x = (t – 2)2 where x is in metres and t in seconds. The distance covered by the particle in first 4 seconds is ______. - Physics

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प्रश्न

The displacement of a particle is given by x = (t – 2)2 where x is in metres and t in seconds. The distance covered by the particle in first 4 seconds is ______.

पर्याय

  • 4 m

  • 8 m

  • 12 m

  • 16 m

MCQ
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उत्तर

The displacement of a particle is given by x = (t – 2)2 where x is in metres and t in seconds. The distance covered by the particle in first 4 seconds is 8 m.

Explanation:

Given, `x = (t - 2)^2`

Velocity, `v = (dx)/(dt) = d/(dt) (t - 2)^2 = 2(t - 2)`  m/s

Acceleration, `a = (dv)/(dt) = d/(dt) [2(t - 2)]`

= `2[1 - 0]`

= 2 m/s2

When t = 0; v = – 4 m/s

t = 2s; v = 0 m/s

t = 4s; v = 4 m/s

v-t graph is shown in the adjacent diagram

Distance travelled = Area of the graph

= Area OAC + Area ABD

= `(4 xx 2)/2 + 1/2 xx 2 xx 4`

= 8 m

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पाठ 3: Motion In a Straight Line - Exercises [पृष्ठ १४]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
पाठ 3 Motion In a Straight Line
Exercises | Q 3.5 | पृष्ठ १४
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