Advertisements
Advertisements
प्रश्न
Consider the following frequency distributions
| Class | 65 - 85 | 85 - 105 | 105 - 125 | 125 - 145 | 145 - 165 | 165 - 185 | 185-205 |
| Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
The difference of the upper limit of the median class and the lower limit of the modal class is?
पर्याय
0
19
20
38
MCQ
Advertisements
उत्तर
20
Explanation:-
| Class | Frequency | Cumulative frequency |
| 65 - 85 | 4 | 4 |
| 85 - 105 | 5 | 9 |
| 105 - 125 | 13 | 22 |
| 125 - 145 | 20 | 42 |
| 145 - 165 | 14 | 56 |
| 165 - 185 | 7 | 63 |
| 185 - 205 | 4 | 67 |
Here, N = 67.
`therefore N/2=33.5,` which lies in the interval 125 - 145.
Therefore, the lower limit of the median class is 125.
The highest frequency is 20, which lies in the interval 125 - 145.
Therefore, the upper limit of modal class is 145.
So, the required difference is 145 - 125 = 20.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
