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प्रश्न
The daily expenditure of 100 families are given below. Calculate f1 and f2 if the mean daily expenditure is ₹ 188.
| Expenditure (in ₹) |
140 – 160 | 160 – 180 | 180 – 200 | 200 – 220 | 220 – 240 |
| Number of families |
5 | 25 | f1 | f2 | 5 |
बेरीज
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उत्तर
The given data is shown as follows:
| Expenditure (in ₹) |
Number of families (fi) | Class mark (xi) | fixi |
| 140-160 | 5 | 150 | 750 |
| 160-180 | 25 | 170 | 4250 |
| 180-200 | `f_1` | 190 | 190`f_1` |
| 200-220 | `f_2` | 210 | 210`f_2` |
| 220-240 | 5 | 230 | 1150 |
| Total | Σfi = 35 + f1 + f2 | Σfixi = 6150 + 190f1 + 210f2 |
Sum of the frequencies = 100
⇒ `∑ f_i` = 100
⇒ 35 + `f_1 + f_2` = 100
⇒` f_1 + f_2` = 100 – 35
⇒ `f_1 + f_2` = 65
⇒ `f_2 = 65 - f_1` ……..(1)
Now, the mean of the given data is given by,
`barx = (sumf_i x_i)/(sumf_i )`
⇒ 188 =`(6150+190f_1+210f_2)/100`
`⇒ 18800 = 6150 + 190f_1 + 210f_2`
`⇒ 18800 - 6150 = 190f_1 + 210f_2`
`⇒ 12650 = 190f_1 + 210(65 - f_1) ` [from (1)]
`⇒ 12650 = 190f_1 - 210f_1 + 13650`
`⇒ 20f_1 = 13650 - 12650`
`⇒ 20f_1 = 1000`
`⇒ f_1 = 50`
If `f_1 = 50`, then `f_2 = 65 - 50 = 15`
Thus, the value of `f_1` is 50 and `f_2` is 15.
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