Question

The current flowing through an inductor of self-inductance L is continuously increasing at constant rate. The variation of induced e.m.f. (e) verses dI/dt is shown graphically by figure

पर्याय

• B

• A

• D

• C

Answer 1

Graph A

Explanation:

Given that, \[\frac {dI}{dt}\] = constant

\[\therefore\] e = -L × constant

This is correctly depicted in graph A.