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प्रश्न
The current flowing through an inductor of self inductance ‘L’ is continuously increasing at constant rate. The variation of induced e.m.f. (e) versus `((dI)/(dt))`is shown graphically by:
पर्याय
A
B
C
D
MCQ
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उत्तर
B
Explanation:
Given that, `((dI)/(dt))` = constant
∴ e = −L × constant
The negative sign indicates that the e.m.f. opposes the change.
Because the current is increasing (`((dI)/(dt))` is positive), the induced e.m.f. must be negative (plotted below the origin).
A direct proportionality with a negative constant results in a straight line passing through the origin in the fourth quadrant (downward).
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