Question

The Crystal Field Stabilisation Energy (CFSE) of [CoF₃(H₂O)₃] (Δ_o > P) is ______.

पर्याय

• −0.4 Δ_o

• −0.8 Δ_o

• −0.4 Δ_o + P

• −0.8 Δ_o + 2P

Answer 1

The Crystal Field Stabilisation Energy (CFSE) of [CoF₃(H₂O)₃] (Δ_o > P) is `bbunderline(-0.4 Δ_o)`.

Explanation:

In the complex [CoF₃(H₂O)₃], the Co³⁺ ion has a 3d⁶ configuration. The complex is octahedral with weak field ligands (F⁻ and H₂O), which makes the complex high-spin.

For a high-spin octahedral complex with d⁶ electrons, the electrons fill the orbitals as follows:

• 4 electrons will occupy the higher-energy e_g orbitals.
• 2 electrons will occupy the lower-energy t_2g orbitals.

The Crystal Field Stabilization Energy (CFSE) is calculated using the formula:

CFSE = (−0.4 Δ_o​ × number of electrons in t_2g​) + (+0.6 Δ_o ​× number of electrons in e_g​)

= (−0.4 Δ_o​ × 4_​) + (+0.6 Δ_o ​× 2​)

= −1.6 Δ_o + 1.2 Δ_o

= −0.4 Δ_o

Thus, the CFSE of [CoF₃(H₂O)₃] is −0.4 Δ_o.