Question

The coordinates of the point equidistant from the vertices O(0, 0), A(6, 0) and B(0, 8) of ΔOAB are ______.

Answer 1

The coordinates of the point equidistant from the vertices O(0, 0), A(6, 0) and B(0, 8) of ΔOAB are (3, 4).

Explanation:

Triangle OAB is right-angled at O (OA ⟂ OB), so the circumcenter point equidistant from all three vertices is the midpoint of the hypotenuse AB.

Midpoint of A(6, 0) and B(0, 8) is `((6 + 0)/2, (0 + 8)/2) = (3, 4)`.