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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

The coefficient of static friction between a coin and a gramophone disc is 0.5. Radius of the disc is 8 cm. Initially the center of the coin is 2 cm away from the center of the disc. At what minimum - Physics

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प्रश्न

The coefficient of static friction between a coin and a gramophone disc is 0.5. Radius of the disc is 8 cm. Initially the center of the coin is 2 cm away from the center of the disc. At what minimum frequency will it start slipping from there? By what factor will the answer change if the coin is almost at the rim? (use g = π2m/s2)

संख्यात्मक
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उत्तर

Given: μs = 0.5

rD = 8 cm = 8 × 10−2 m

rC = 2 cm = 2 × 102 m

Fmin = ?

mrω2 = μN

mrω2 = μ mg      ...[N = mg]

∴ ω2 = `(mu g)/r`

⇒ 4 π2 f2 = `(0.5 xx pi^2)/(2 xx 10^-2)`    ...[ω = 2 π f ⇒ ω2 = 22 π2 f2 ⇒ ω2 = 4 π2 f2]

⇒ `4 cancel(pi^2)f^2 = (0.5 xx cancel(pi^2))/(2 xx 10^-2)`

⇒ f2 = `(0.5 xx 10^2)/(4 xx 2)`

⇒ f2 = `50/8`

⇒ f2 = `25/4`

⇒ f = `5/2 = 2.5` rev/s

`f prop 1/sqrtr, f_n prop 1/sqrt(r_n)`

`f_n/f = sqrt(r/r_n)`

= `sqrt((2 xx 10^-2)/(8 xx 10^-2))`

= `sqrt(1/4)`

fn = `1/2 f`

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Rotational Dynamics
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पाठ 1: Rotational Dynamics - Exercises [पृष्ठ २४]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
पाठ 1 Rotational Dynamics
Exercises | Q 13 | पृष्ठ २४

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