Advertisements
Advertisements
प्रश्न
The area of ΔABC with vertices A(3, 0), B(7, 0) and C(8, 4) is ______.
पर्याय
14 sq units
28 sq units
8 sq units
6 sq units
MCQ
रिकाम्या जागा भरा
Advertisements
उत्तर
The area of ΔABC with vertices A(3, 0), B(7, 0) and C(8, 4) is 8 sq units.
Explanation:
AB lies on the x-axis from x = 3 to x = 7, so base AB = 4.
The y-coordinate of C is 4, so the height from C to AB is 4.
Area = `1/2` × base × height
= `1/2 xx 4 xx 4`
= 8 sq units
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
