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प्रश्न
The A.P. 8, 10, 12, ....... has 60 terms. Find the sum of the last 10 terms.
बेरीज
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उत्तर
Given A.P. is 8, 10, 12, ......., 60 terms.
Number of terms (n) = 60
First term (a) = 8
Common difference (d) = 2
We need the sum of the last 10 terms, i.e.,
t51 + t52 + ..... + t60
Use the nᵗʰ term formula:
tn = a + (n − 1)d
Find the 60th term:
t60 = 8 + (60 − 1)(2)
t60 = 8 + 59(2)
t60 = 8 + 118
t60 = 126
Find the 51st term:
t51 = 8 + (51 − 1)(2)
t51 = 8 + 50(2)
t51 = 8 + 100
t51 = 108
Now, find the sum of the last 10 terms.
Formula for sum of n terms:
`S_n = n/2 (t_51 + t_60)`
`S_10 = 10/2(108 + 126)`
S10 = 5 × 234
S10 = 1170
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