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प्रश्न
The angle of elevation of the top of a building from a point 50 m away from its foot is 60°. Find the height of the building.
बेरीज
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उत्तर
Given: Angle of elevation = 60°, horizontal distance from foot = 50 m.
Step-wise calculation:
1. Let h be the height of the building.
In the right triangle formed.
`tan 60^circ = "Opposite"/"Adjacent"`
= `h/50`
2. `tan 60^circ = sqrt(3)`.
So, `sqrt(3) = h/50`.
3. `h = 50 xx sqrt(3)`.
Height = `50sqrt(3)` m ≈ 86.60 m to two decimal places.
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