मराठी

The angle between the tangents to the circle x2 + y2 = 25 from the point (7, -1) is ______.

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प्रश्न

The angle between the tangents to the circle x2 + y2 = 25 from the point (7, -1) is ______.

पर्याय

  • `pi/3`

  • `pi/6`

  • `pi/4`

  • `pi/2`

MCQ
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उत्तर

The angle between the tangents to the circle x2 + y2 = 25 from the point (7, -1) is `underline(pi/2)`.

Explanation:

The equation of the circle is x2 + y2 = 25

∴ radius a = 5

Let P = (7, -1)

Let the equation of a tangent to the given circle from P be

y = mx ± a`sqrt(1 + "m"^2)`

∴ y = mx ± 5`sqrt(1 + "m"^2)`

As P(7, - 1) lies on tangent, we have

-1 = 7m ± 5`sqrt(1 + "m"^2)`

⇒ (7m + 1)2 = 25(1 + m2)

⇒ 49m2 + 1 + 14m = 25 + 25m2

⇒ 24m2 + 14m - 24 = 0

⇒ 12m2 + 7m - 12 = 0

⇒ m = `3/4, - 4/3`

Let m1 = `3/4` and m2 = `-4/3`

Then, m1m2 = - 1

Hence, the angle between the tangents is `pi/2`

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