मराठी

The action of heat of the blue crystalline solid L gives a reddish brown gas M, is which re-light a glowing splint and leave a black residue. (i) Identify L, M and N (Name and formula).

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प्रश्न

The action of heat of the blue crystalline solid L gives a reddish brown gas M, is which re-light a glowing splint and leave a black residue. When gas N, which has a rotten egg smell, is passed through a solution of L a black precipitate is formed.

  1. Identify L, M and N (Name and formula).
  2. Write the equation for the action of heat.
  3. Write the equation for the reaction between the solution of L and the gas M.
लघु उत्तर
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उत्तर

i. L is copper nitrate [Cu(NO3)2]. 

M is nitrogen dioxide [NO2].

N is hydrogen sulphide [H2S].

ii. \[\ce{\underset{Blue crystalline}{2Cu(NO3)2} ->[heat] \underset{Black}{2CuO} + 4NO2 + O2}\]

iii. When a H2S gas, which has a rotten egg smell, is passed through a solution of Cu(NO3)2, a black ppt. of CuS is formed.

\[\ce{Cu(NO3)2 + H2S ->CuS + 2HNO3}\]

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पाठ 3: Acids, Bases and Salts - EXERCISE [पृष्ठ ७७]

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लखमीर सिंह Chemistry [English] Class 10 ICSE
पाठ 3 Acids, Bases and Salts
EXERCISE | Q 9. | पृष्ठ ७७
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